chicken delight sells whole-chicken dinners for $12 and half-chicken dinners for $8. yesterday they sold a total of 400 dinners and took in $4200. how many of each size dinners were sold?
Use algebra to solve this. Let x be the number of whole-chicken dinners sold, and y be the number of half-chicken dinners.
x + y = 400 (the number sold)
12x + 6y = 4200 (gross receipts)
12x + 12y = 4800
6y = 600
Two more steps and you will have the answer. You finish the problem.
whole 250.half 150
Let's assume that x represents the number of whole-chicken dinners sold and y represents the number of half-chicken dinners sold.
Based on the given information, we can form two equations:
1. $12x + $8y = $4200 (equation 1: total revenue)
2. x + y = 400 (equation 2: total number of dinners)
To solve this system of equations, we can use the substitution method.
From equation 2, we can express x in terms of y:
x = 400 - y
Substituting this value of x into equation 1:
$12(400 - y) + $8y = $4200
Expanding and simplifying the equation:
4800 - 12y + 8y = 4200
Combine like terms:
-4y = -600
Dividing both sides by -4:
y = 150
Substituting this value of y back into equation 2:
x + 150 = 400
Subtracting 150 from both sides:
x = 250
Therefore, 250 whole-chicken dinners and 150 half-chicken dinners were sold.
To solve this problem, we can use a system of equations. Let's assume that x represents the number of whole-chicken dinners sold, and y represents the number of half-chicken dinners sold.
We're given two pieces of information:
1. The total number of dinners sold is 400: x + y = 400.
2. The total amount of money collected is $4200: 12x + 8y = 4200.
Now we have a system of equations. We can solve it using various methods, such as substitution or elimination.
Let's use the substitution method:
From the first equation, we have:
x = 400 - y.
Now we can substitute this value of x in the second equation:
12(400 - y) + 8y = 4200.
Expanding the equation gives:
4800 - 12y + 8y = 4200.
Combining like terms:
-4y = -600.
Dividing both sides by -4 gives:
y = 150.
Now we substitute the value of y back into the first equation:
x + 150 = 400.
Subtracting 150 from both sides gives:
x = 250.
So, 250 whole-chicken dinners and 150 half-chicken dinners were sold.