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Posted by **Physics** on Saturday, July 11, 2009 at 9:20pm.

A lbock is given an intial speed of 4.0 s^-1 m up the 22 degree plane

How far up the plane will it go

ok I got this to be something like 2.2 about i understand this

i need help on this

how much time elapses before it returns to tis starting point? Ignore friction.

ok I need to know what formula to use to rearange for time

i thought it was this

x = 2^-1 a t^2 + Vo t + Xo

if i'm right then i guess I do not know how to rearange this for time because ther's a t^2 and t so could show me how to rearange this for time

thanks

ok and to find the distance i did this formula

V^2 = Vo^2 + 2a(X-Xo)

rearanged for X

x = (2a)^-1 (-Vo)^2

and if i did that correctly

I got 2.2 m so is this a valid way to doing this also

by the way I was told from

drwls this

You could also solve

y = V t - (a/2) t^2 = 0

to get the answer. Ignore the t=0 solution.

t = 8/a = 2.2

to solve for time

I just want to confirm that you had to resolve the Vo into it's componetns right to get Vo in the y direction correct and used gravity for accelration???

- Physics -
**Physics**, Saturday, July 11, 2009 at 9:29pmhmmm aparently that's not how you do it

hmmm could you please show me how to get the time step by step

don't you have to use this equation

X = 2^-1 a t^2 + Vo t + Xo

write it in the second dimension

Y = 2^-1 g t^2 + Vo t + Yo

and sense there is no Yo

I get this

Y = 2^-1 g t^2 + Vo t

still not enoguh to solve for time

so I don't get it

for the y component of the inital velocity I got about 1.498 s^-1 m

I do belive there is one...

- Physics -
**bobpursley**, Saturday, July 11, 2009 at 9:35pmIf you start at the top, there is no initial velocity. Find the time downward, then double if for the entire trip.

- Physics -
**Physics**, Saturday, July 11, 2009 at 9:47pmoh... lol thanka

- ONE MORE QUESTION -
**WAIT ONE MORE QUESTION**, Saturday, July 11, 2009 at 9:50pmlol ok um so then I have this equation

y = 2^-1 g t^2

ok I get it

however I do not know y

how do I get y

thanks

thanks for helping me solve this problem

- i get it now -
**oh ok...**, Saturday, July 11, 2009 at 9:52pmthanks

so the equation is

x = 2^-1 a t^2

were I know a is about 3.671 s^-1 m

thanks guys!

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