Posted by Matrix School 2 on Saturday, July 11, 2009 at 1:43pm.
consider the relation R=[(1,2),(2,5),(3.10),(4,17),(5,26)]. find the
i)range ii)domain iii)inverse

Set theory  MathMate, Saturday, July 11, 2009 at 4:21pm
Assuming the relation is
f(x)=y=x^{2}+1 where x ∈ ℕ (i.e. x is a member of natural numbers), then the domain is
{x:[1,5] ∈ ℕ}
Range is
{y:[2,26] ∈ ℕ}
Inverse:
f^{1}(y) = sqrt((y1)) : f^{1}(y)>0

Set theory  MathMate, Saturday, July 11, 2009 at 4:29pm
Correction for range, which is the set of all values produced by the function within the given domain. For the above relation
f(x)=y=x^{2}+1,
the domain is
{1,2,3,4,5}
the range is
{2,5,10,17,26}
The inverse is as above.
Answer This Question
Related Questions
 Algebra  23. The ___ axis represents the independent variable. X? 21. Name the ...
 math  indicates required items An operation * is defined by the relation x*y = ...
 Discreet Mathematics  Part I: Suppose you are developing a statistical database...
 Advanced Algebra  What is the inverse of each of the functions defined by the ...
 Calc  range of f(x)= 5^(2x^21)^(1/2) i know that the domain of the inverse ...
 Precalculus  Given the following values for f(t): t : f(t) 3 : 7 6 : 6 9 : 19...
 algebra  1 (a) A function passes through the points (0, 5), (1, 0), (2, 7). ...
 Precalculus  The question(s) are as follows: Given: f(x) = 3cos(3x+π)  4 ...
 Algebra  What is the domain and range of the relation y = 2(x5)^2 + 8? Express...
 calculus  Consider the function . a. Find the domain and range of h. b. What is...
More Related Questions