Set theory
posted by Matrix School 2 on .
consider the relation R=[(1,2),(2,5),(3.10),(4,17),(5,26)]. find the
i)range ii)domain iii)inverse

Assuming the relation is
f(x)=y=x^{2}+1 where x ∈ ℕ (i.e. x is a member of natural numbers), then the domain is
{x:[1,5] ∈ ℕ}
Range is
{y:[2,26] ∈ ℕ}
Inverse:
f^{1}(y) = sqrt((y1)) : f^{1}(y)>0 
Correction for range, which is the set of all values produced by the function within the given domain. For the above relation
f(x)=y=x^{2}+1,
the domain is
{1,2,3,4,5}
the range is
{2,5,10,17,26}
The inverse is as above.