How do I write out the reactants and products for the following chemical equation? How do I write the names of the products? How do I write the net ionic reaction for this double replacement reaction?
barium acetate and potassium phosphate ->
To write out the reactants and products for the given chemical equation, you need to understand the reactants and products involved in the reaction.
The reactants in this case are barium acetate (Ba(C2H3O2)2) and potassium phosphate (K3PO4).
To write out the products, we need to determine what compounds or molecules are formed when these reactants combine. In a double replacement reaction, the positive ions (cations) switch places between the reactants, resulting in the formation of new compounds.
So, when barium acetate reacts with potassium phosphate, the positive ion (barium ion) from barium acetate will combine with the negative ion (phosphate ion) from potassium phosphate, while the positive ion (potassium ion) from potassium phosphate combines with the negative ion (acetate ion) from barium acetate.
This will lead to the formation of two products: barium phosphate (Ba3(PO4)2) and potassium acetate (KCH3COO).
To write the net ionic reaction, you should first write the balanced chemical equation:
3Ba(C2H3O2)2 + 2K3PO4 -> Ba3(PO4)2 + 6KCH3COO
Next, we need to identify the ions that are actually involved in the reaction. In this case, the acetate ion (C2H3O2-) and potassium ion (K+) do not participate in the reaction because they remain separate and unchanged on both sides.
Therefore, the net ionic reaction, which only includes the species that actually participate in the reaction, is:
3Ba2+ + 2PO43- -> Ba3(PO4)2
Ba(C2H3O2)2 + K3PO4 ==> Ba3(PO4)2 + KC2H3O2
The products are barium phosphate and potassium acetate.
The secret words in the question are "double replacement reaction." Note that the Ba of the first compound goes with the PO4 from the second (positive of first goes with negative of the second) while the C2H3O2 of the first goes with the K of the second (negative of the first goes with the positive of the second). I have not balanced the equation. I'll leave that for you.
To do the net ionic equation, two steps are necessary and I will leave those for you.
Step 1. Write those compounds that dissolve in water as ions. For example, Ba(C2H3O2)2 will be written as Ba^+2 _ 2C2H3O2^-.
Compounds that are gases (there are none) or weak electrolytes (there are none) or solids (take a look at the solubility table for Ba3(PO4)2) are written as the compound (not broken up into ions).
Step 2. Cancel ions that appear on both sides of the equation.
When you finish, the net ionic equation should be 3Ba^+2(aq) + 2PO4^-3(aq) ==>Ba3(PO4)2(s)
Here is the site for solubility.
http://www.files.chem.vt.edu/RVGS/ACT/notes/solubility_rules.html