Monday

July 28, 2014

July 28, 2014

Posted by **Bonnie** on Wednesday, July 8, 2009 at 3:18pm.

4x^2 – 16x + 25 = 0.

- Algebra -
**Marth**, Wednesday, July 8, 2009 at 3:25pmThe exact question was asked by Pamela yesterday. I have copied down my solution. For more information, view the entire thread.

(a) The equation is in the form ax^2 + bx + c

Use those values for b^2 - 4ac.

(-16)^2 - 4*4*25

= 256 - 400

= -144

The determinant is negative, so there will be two imaginary solutions.

(b) The quadratic equation is x = (-b +/- sqrt(determinant))/(2a)

Using the values of a, b, and c from the equation, we get

x = (16 +/- sqrt(-144))/(2*4)

x = (16 +/- 12i)/8

x = 2 +/- 3i/2

**Related Questions**

Algebra - Consider the equation: 4x^2 – 16x + 25 = 0 (a) Show how to compute the...

Algebra - Consider the equation 4x^2 – 16x + 25 = 0. (a) Show how to compute the...

Algebra 2 - Can you show your work please :/ 12. Use the quadratic formula to ...

Algebra Help - Solve. Find the exact solution(s). Simplify as much as possible. ...

Algebra - Solve. Find the exact solution(s). Simplify as much as possible. Show ...

Algebra II - 1)What method(s) would you choose to solve the equation: x2 + 2x - ...

Algebra - For this equation x^(2) + x + 2 which you can't factor but then you ...

Math - Find the real solutions, if any, to this equation. Use the quadratic ...

Algebra II? - I am having trouble with these. I don't even know where to start: ...

algebra II - How do you know if a quadratic equation will have one, two, or no ...