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November 28, 2014

November 28, 2014

Posted by **Bonnie** on Wednesday, July 8, 2009 at 3:18pm.

4x^2 – 16x + 25 = 0.

- Algebra -
**Marth**, Wednesday, July 8, 2009 at 3:25pmThe exact question was asked by Pamela yesterday. I have copied down my solution. For more information, view the entire thread.

(a) The equation is in the form ax^2 + bx + c

Use those values for b^2 - 4ac.

(-16)^2 - 4*4*25

= 256 - 400

= -144

The determinant is negative, so there will be two imaginary solutions.

(b) The quadratic equation is x = (-b +/- sqrt(determinant))/(2a)

Using the values of a, b, and c from the equation, we get

x = (16 +/- sqrt(-144))/(2*4)

x = (16 +/- 12i)/8

x = 2 +/- 3i/2

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