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December 18, 2014

December 18, 2014

Posted by **Tammie** on Wednesday, July 8, 2009 at 10:15am.

4x^2 – 16x + 25 = 0

(a) Show how to compute the discriminant, b^2 – 4ac, and then state whether there is one real-number solution, two different real-number solutions, or two different imaginary-number solutions.

(b) Use the quadratic formula to find the exact solutions of the equation. Show work. Simplify the final results as much as possible.

- Algebra -
**bobpursley**, Wednesday, July 8, 2009 at 10:18amWhat is your question. The problem is rather self-explanatory.

- Algebra -
**Tammie**, Wednesday, July 8, 2009 at 10:50amThis is my first time doing a problem like this and need some guidence. I have 5 more problems like this one and would like some help so I know how to do the rest. Thanks!

- Algebra -
**Reiny**, Wednesday, July 8, 2009 at 11:14amThe page will give you a good head-start.

http://www.mathnstuff.com/math/spoken/here/2class/320/quadequ.htm

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