Posted by **Angie** on Tuesday, July 7, 2009 at 7:43pm.

Solve the equation. Check all proposed solutions. Show work in solving and in checking.

Root3-x = x-1

- Algebra -
**Marth**, Tuesday, July 7, 2009 at 7:48pm
sqrt(3-x) = x-1.

Start by squaring both sides.

3 - x = x^2 - 2x + 1

0 = x^2 - x - 2

Factor the equation:

0 = (x-2)(x+1)

So x = 2 or x = 1

- Algebra -
**annaiiz ceballos**, Tuesday, July 7, 2009 at 7:51pm
you made a mistake it is x=2 or x=1 its x=2 or x=-1

- Algebra -
**Angie**, Tuesday, July 7, 2009 at 7:54pm
I am still confused. Can someone please explain further and break this problem down cause I have 5 more like this one to do. Thank you!

- But......Algebra -
**Reiny**, Tuesday, July 7, 2009 at 8:10pm
from Marth's last line

So x = 2 or x = 1 ...

that should have said

So x = 2 or x = -1

Since he squared both sides, all answers must be verified.

if x=2

LS = √(3-2) = √1 = 1

RS = 2-1 = 1 OK

if x = -1

LS = √(3+1) = √4 = 2

RS = -1 - 1 = -2

so LS is not equal to RS

so the only solution is x = 2

- Algebra -
**Angie**, Tuesday, July 7, 2009 at 8:17pm
2 or 1 or

2 or -1?

annaiiz ceballos said

it is x=2 or x=1 its x=2 or x=-1

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