Posted by Chase on Monday, July 6, 2009 at 2:26pm.
I believe you mean (2/(x+5) + 4/(x+3))*(x+3)(x+5)/(3x+13)
Distribute the (x+3)(x+5)/(3x+13)
2(x+3)/(3x+13)+4(x+5)/(3x+13)
They have the same denominator, so you can add them:
(2(x+3)+4(x+5))/(3x+13)
Simplify the numerator:
(2x+6+4x+20)/(3x+13)
(6x+26)/(3x+13)
Divide by (3x+13):
2(3x+13)/(3x+13) = 2
a^+14a-51=0
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