Posted by Physics on Sunday, July 5, 2009 at 5:38pm.
I can offer a suggestion to get you started. The time is the easiest part of the problem to solve because the initial speed of the ball controls ONLY how far away from the base it falls. It does not control the time it takes to fall to the ground. distance = 1/2(g)t^2 where the distance the ball falls is 9 m. Solve for t.
The ball is thrown horizontally, so there is only an initial x velocity. You can find the time interval as shown below.
Start by finding the time the ball is in the air.
d = Vi(t) + 0.5(a)(t^2)
Acceleration is due to gravity. Initial velocity in the y direction is 0 because the ball is thrown horizontally.
9 = 0.5(-9.81)(t^2)
t = 1.355s
Now use V = d/t to find the horizontal velocity.
V = d/t
V = 8.5/1.355
V = 6.3m/s in the x direction
thanks a bunch I guess i didn't see the importance of the word horizontal
THANKS!!
Related Questions
Physics - A ball thrown horizontally at 18.3 m/s from the roof of a building ...
Physics - A ball is thrown horizontally from the roof of a building 55 m tall ...
physics - A ball is thrown horizontally from the roof of a building 59.0 tall ...
physics - A ball is thrown horizontally from the roof of a building 33.0 m tall ...
physics - A ball thrown horizontally at 17.0 m/s from the roof of a building ...
physics - A ball is thrown horizontally from the roof of a building 60 m tall ...
physics - A ball thrown horizontally at 22.3 m/s from the roof of a building ...
Physics - A ball thrown horizontally at 22.3 m/s from the roof of a building ...
Physics(urgent) - A ball is thrown horizontally from the roof of a building 58.5...
high school physics - a ball is thrown hirizontally from the roof of a building ...
For Further Reading