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September 16, 2014

September 16, 2014

Posted by **Preston** on Saturday, July 4, 2009 at 12:38pm.

68;68;63;75;75;63;46;67;75;75;75;68;71;65;61;68;70;72;72;70;70;71;81;84;85;85;80;79;80;80 and those are 30 consecutive days of the month last year. what is the expected value. or expected temp?

- Math -
**Ms. Sue**, Saturday, July 4, 2009 at 12:40pmAdd the temperatures together and divide by 30 to get the average temperature.

Arrange the temperatures in numerical order and find the middle to find the median temperature.

- Math -
**Preston**, Saturday, July 4, 2009 at 12:46pmi know how to find the mean and the median but i need to know how to find the expected value of the set.

- Math -
**Count Iblis**, Saturday, July 4, 2009 at 1:50pmThe expected value is the same as the average. You could also compute the standard deviation which gives you an indication of how much the actual temperature can differ from the expectation value.

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