Posted by **scooby9132002** on Saturday, July 4, 2009 at 1:29am.

In 1990, the life expectancy of males in a certain country was 72.4 years. In 1994, it was 75.8 years...?

Let E represent the life expectancy in year t and let t represent the number of years since 1990.

The linear function E(t) that fits the data is

E(t)=__t + ___. (round to the nearest tenth)

Use the function to predict the life expenctancy of males in 2008.

E(18)=___. (round to the nearest tenth)

- math -
**Reiny**, Saturday, July 4, 2009 at 7:31am
basically you are asked to find the linear function E(t)

given two points, (0,72.4) and (4,75.8)

slope = (75.8-72.4)/(4-0) = .85

so E(t) = .85t + b (compare with y = mx + b)

sub in (0,72.4) to solve for b

then evaluate E(18) by subbing in t = 18

## Answer This Question

## Related Questions

- math - in 1990 the life expectancy of males in a certain country was 64.7 years...
- math - in 1994 the life expectancy of malews in a certain country was 70.9 years...
- math (word problem) - In 1994, the life expectancy of males in a certain ...
- math - In 1990, the life expectancy of males in a certain country was 62.1 years...
- math - In 1990, the life expectancy of males in a certain country was 62.1 years...
- algebra - In 1990, the life expectancy of males in a certain country was 62.1 ...
- Algebra - In 1994 the life expectancy of males in a certain country was 61.6 ...
- Algebra - In 1994, the life expectancy of males in a certain country was 63.8 ...
- algebra - In 1990, the life expectancy of males in a certain country was 62.1 ...
- Algebra - In 1994, the life expectancy of males in a certain country was 64.8 ...

More Related Questions