determine whether (-5,1) is a solution of 9x-9y= -3

I said no am i correct?

solve by elimination mehtod. 2x+3y=4, 4x+6y=8 type as ordered pair, type N for no solution, I for many.

I chose I am I correct?

How did you determine that the answer was "no" to the first one?

BTW. you were right.

For the second, what happens if you multiply your first equation by 2 ?

- So how many lines are you intersecting by solving ?

- Wouldn't any point that works for the first also work for the second ?

- How many points are on the first line ?
So .....

To determine whether (-5,1) is a solution of the equation 9x - 9y = -3, we need to substitute the values of x and y into the equation and check if the equation holds true.

Plugging in x = -5 and y = 1, we have:
9(-5) - 9(1) = -45 - 9 = -54 ≠ -3

Since -54 is not equal to -3, the point (-5,1) is not a solution to the equation 9x - 9y = -3. Therefore, your answer of "no" is correct.

Now, let's solve the system of equations using the elimination method.

1. Start with the equations:
2x + 3y = 4
4x + 6y = 8

2. To eliminate the variable x, we can multiply the first equation by 2 and the second equation by -1:
(2)(2x + 3y) = (2)(4)
(-1)(4x + 6y) = (-1)(8)

This gives us:
4x + 6y = 8
-4x - 6y = -8

3. Adding the two equations eliminates the variable x:
(4x + 6y) + (-4x - 6y) = 8 + (-8)
0 = 0

The result is 0 = 0, which means the equations are equivalent. This indicates that the system has infinitely many solutions.

Therefore, your answer of "I" (many solutions) is correct.