Math
posted by Rita on .
3a2b=12
2a+b=1
multiply eq 2 x 2
4a+2b=2
eliminate b by subtracting eq (1) from (3)
4a+2b=2
3a2b=12
a=10 am i going right so far??

Yes, that looks correct.
Continue by substituting in a=10 into one of the equations to find b.