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December 19, 2014

December 19, 2014

Posted by **Sally** on Thursday, July 2, 2009 at 11:32am.

- Math -
**MathMate**, Thursday, July 2, 2009 at 6:03pmI do not know exactly how the question is worded in case some parentheses are missing.

Case 1:

(3/8)a^{3y}^{5}

... no change required.

Case 2:

use the identity

1/a^{m}= a^{-m}

3/(8a^{3}y^{5})

=(3/8)a^{-3}y^{-5}

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