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Posted by on Thursday, July 2, 2009 at 12:46am.

Liquid methanol (CH3OH) is combusted in oxygen gas to yield carbon dioxide gas and liquid water


Okay I keep getting this:
CH3OH(l) + 1.5 O2(g) > CO2(g) + 2 H2O(l)
the website tells me I'm wrong, but I don't know how to go about with out using fractions. Please help. Thanks

  • Chemistry - , Thursday, July 2, 2009 at 1:02am

    CH3OH(l) + 1.5 O2(g) > CO2(g) + 2 H2O(l)
    You get rid of fractions in chemistry the same as in math. If it's a 1/2, just multiply by 2.
    2CH3OH + 3O2 ==> 2CO2 + 4H2O
    For 1/3 multiply by 3.For 1/4 multiply by 4, etc.
    MOST times we need whole numbers to balance an equation. The only time that fractions are ok is in thermodynamic equations.

  • Chemistry - , Thursday, July 2, 2009 at 1:08am

    thank you sooo much

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