Chemistry
posted by Jason on .
Liquid methanol (CH3OH) is combusted in oxygen gas to yield carbon dioxide gas and liquid water
Okay I keep getting this:
CH3OH(l) + 1.5 O2(g) > CO2(g) + 2 H2O(l)
the website tells me I'm wrong, but I don't know how to go about with out using fractions. Please help. Thanks

CH3OH(l) + 1.5 O2(g) > CO2(g) + 2 H2O(l)
You get rid of fractions in chemistry the same as in math. If it's a 1/2, just multiply by 2.
2CH3OH + 3O2 ==> 2CO2 + 4H2O
For 1/3 multiply by 3.For 1/4 multiply by 4, etc.
MOST times we need whole numbers to balance an equation. The only time that fractions are ok is in thermodynamic equations. 
thank you sooo much