Posted by Jason on Thursday, July 2, 2009 at 12:46am.
Liquid methanol (CH3OH) is combusted in oxygen gas to yield carbon dioxide gas and liquid water
Okay I keep getting this:
CH3OH(l) + 1.5 O2(g) > CO2(g) + 2 H2O(l)
the website tells me I'm wrong, but I don't know how to go about with out using fractions. Please help. Thanks

Chemistry  DrBob222, Thursday, July 2, 2009 at 1:02am
CH3OH(l) + 1.5 O2(g) > CO2(g) + 2 H2O(l)
You get rid of fractions in chemistry the same as in math. If it's a 1/2, just multiply by 2.
2CH3OH + 3O2 ==> 2CO2 + 4H2O
For 1/3 multiply by 3.For 1/4 multiply by 4, etc.
MOST times we need whole numbers to balance an equation. The only time that fractions are ok is in thermodynamic equations. 
Chemistry  Jason, Thursday, July 2, 2009 at 1:08am
thank you sooo much