Posted by **Jason** on Wednesday, July 1, 2009 at 7:41pm.

April buys eight books for $44. Paper back books cost $4 and hard back books cost $8. How many of

each book did she buy?

- Math -
**Marina**, Wednesday, July 1, 2009 at 8:39pm
4 paper backs and 4 hard cover

- Math -
**Ms. Sue**, Wednesday, July 1, 2009 at 8:42pm
Hmm -- that's not right.

4 * 4 = 16

4 * 8 = 32

16 + 32 = 48.

Ooops!

- Math -
**MathMate**, Wednesday, July 1, 2009 at 9:30pm
For this kind of problem, I usually start off with all paperbacks, thus 8*4=$32.

Since I am short 44-32=$12, and changing from a paperback to a hard-cover costs 8-4=$4, So I must have bought 3 hard-covers and 8-3=5 paperbacks.

Check: 3*8+5*4=24+20=$44.

- Math -
**DrBob222**, Wednesday, July 1, 2009 at 10:46pm
And then there's the LONG way of doing it.

H = number of hard covers.

P = number of paper covers.

===========================

H + P = 8

8H + 4P = 44.

================

Two equations in two unknowns. Solve for H and P.

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