Saturday

July 26, 2014

July 26, 2014

Posted by **Jason** on Wednesday, July 1, 2009 at 7:41pm.

each book did she buy?

- Math -
**Marina**, Wednesday, July 1, 2009 at 8:39pm4 paper backs and 4 hard cover

- Math -
**Ms. Sue**, Wednesday, July 1, 2009 at 8:42pmHmm -- that's not right.

4 * 4 = 16

4 * 8 = 32

16 + 32 = 48.

Ooops!

- Math -
**MathMate**, Wednesday, July 1, 2009 at 9:30pmFor this kind of problem, I usually start off with all paperbacks, thus 8*4=$32.

Since I am short 44-32=$12, and changing from a paperback to a hard-cover costs 8-4=$4, So I must have bought 3 hard-covers and 8-3=5 paperbacks.

Check: 3*8+5*4=24+20=$44.

- Math -
**DrBob222**, Wednesday, July 1, 2009 at 10:46pmAnd then there's the LONG way of doing it.

H = number of hard covers.

P = number of paper covers.

===========================

H + P = 8

8H + 4P = 44.

================

Two equations in two unknowns. Solve for H and P.

**Related Questions**

algebra - April buys 8 books for $44.1 paper back book costs$4 and 1 hard back ...

Math - Suppose you intend to spend no more than $60 buying books. Hardback books...

math - for every 20 math books a school buys, they they get 7 aditional books ...

MATHS - Mrs.Koh purchased new books for the school library, of which 6 were ...

Math - 5 books and 9 magazines cost $150.50 dollars altogether. 9 Books and 5 ...

Math - 5 books and 9 magazines cost $150.50 altogether. 9 books and 5 magazines ...

MATHS - A store clerk sold 25 maths books and 10 english books for $855.00 .if ...

math - MEghan had 36 books in her locker. Some were library books, text books ...

math - Lan has 6 books for each book he has 2 science books he has 2 animl books...

Arithmetic - A box in a college bookstore contains books, and each book in the ...