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November 24, 2014

November 24, 2014

Posted by **Jason** on Wednesday, July 1, 2009 at 7:41pm.

each book did she buy?

- Math -
**Marina**, Wednesday, July 1, 2009 at 8:39pm4 paper backs and 4 hard cover

- Math -
**Ms. Sue**, Wednesday, July 1, 2009 at 8:42pmHmm -- that's not right.

4 * 4 = 16

4 * 8 = 32

16 + 32 = 48.

Ooops!

- Math -
**MathMate**, Wednesday, July 1, 2009 at 9:30pmFor this kind of problem, I usually start off with all paperbacks, thus 8*4=$32.

Since I am short 44-32=$12, and changing from a paperback to a hard-cover costs 8-4=$4, So I must have bought 3 hard-covers and 8-3=5 paperbacks.

Check: 3*8+5*4=24+20=$44.

- Math -
**DrBob222**, Wednesday, July 1, 2009 at 10:46pmAnd then there's the LONG way of doing it.

H = number of hard covers.

P = number of paper covers.

===========================

H + P = 8

8H + 4P = 44.

================

Two equations in two unknowns. Solve for H and P.

**Answer this Question**

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