two tuning forks are struck at the same time. one tuning forkhas a frequency of 20hz while the second tuning fork has a frequency of 226 hz. How many beats will result?

Responses

science - bobpursley, Tuesday, June 30, 2009 at 5:05pm
you get the sum and difference, or 206 and 246

science - anonyomous, Tuesday, June 30, 2009 at 8:10pm
i see i don't understand how you got the answer though

226-20 = 206 Hz.

226 + 20 = 246 Hz.

To determine the number of beats that will result from two tuning forks with different frequencies, you follow these steps:

1. Find the absolute difference between the frequencies of the two tuning forks.

2. Divide that difference by 2 to get the frequency of the beats produced.

Let's apply this to the given example:

1. The absolute difference between the frequencies of the two tuning forks is calculated by subtracting the lower frequency from the higher frequency: 226 Hz - 20 Hz = 206 Hz.

2. Divide the difference by 2 to find the frequency of the beats: 206 Hz / 2 = 103 Hz.

Therefore, the resulting beats will have a frequency of 103 Hz.