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October 2, 2014

October 2, 2014

Posted by **Carmin** on Tuesday, June 30, 2009 at 10:11pm.

- Math Word Problem -
**MathMate**, Tuesday, June 30, 2009 at 10:24pmLet x,y be the side of each of the squares.

x^{2}+ y^{2}= 1000

y=(2/3)x-10

substitute (2/3)x-10 for y in the first equation:

x^{2}+ ((2/3)x-10)^{2}= 1000

Expand and solve for the quadratic equation to get x=30 or x=-270/13.

Reject second solution to get x=30, y=10

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