two tuning forks are struck at the same time. one tuning forkhas a frequency of 20hz while the second tuning fork has a frequency of 226 hz. How many beats will result?

Didn't I answer this earlier? What was wrong with that?

i didn't realize it sorry

To determine the number of beats that will result when two tuning forks are struck at the same time, you need to know the difference in frequency between the two tuning forks.

The formula for calculating the number of beats is:

Number of Beats = |f1 - f2|

Where:
- f1 is the frequency of the first tuning fork
- f2 is the frequency of the second tuning fork

In this case, the frequency of the first tuning fork is 20 Hz, and the frequency of the second tuning fork is 226 Hz.

Plugging in the values into the formula:

Number of Beats = |20 Hz - 226 Hz|

Taking the absolute value of the difference:

Number of Beats = |-206 Hz|

Therefore, the number of beats that will result is 206 beats.