Thursday

July 31, 2014

July 31, 2014

Posted by **Katrina** on Tuesday, June 30, 2009 at 6:27pm.

- Algebra -
**MathMate**, Tuesday, June 30, 2009 at 10:33pmLet x,y be the side of each of the squares.

x2 + y2 = 1000

y=(2/3)x-10

substitute (2/3)x-10 for y in the first equation:

x2 + ((2/3)x-10)2 = 1000

Expand and solve for the quadratic equation to get x=30 or x=-270/13.

Reject second solution to get x=30, y=10

See also

http://www.jiskha.com/display.cgi?id=1246414274

**Related Questions**

Algebra - Babylonian Problem - circa 1800 BC An area, A, consisting of the sum ...

Algebra - Babylonian Problem - circa 1800 BC An area, A, consisting of the sum ...

Math Word Problem - An area, A, consisting of the sum of two squares is 1000. ...

Algebra 1 - A landscaper has two gardens: one is a square and the other is a ...

Algebra 1 - You are designing a wall mural that will be composed of squares of ...

math/algebra - I have a triangle one side = 3 side 2 = square root5 - square ...

math - The length of a side of a square is fifteen less than four times the ...

math - a rectangle has the length twice the side of this square and width three ...

Algebra - A square and an equilateral triangle has the same perimeter. Each side...

Algebra - Suppose a square garden has an area represented by 9x^2 square feet. ...