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November 27, 2014

November 27, 2014

Posted by **Katrina** on Tuesday, June 30, 2009 at 6:27pm.

- Algebra -
**MathMate**, Tuesday, June 30, 2009 at 10:33pmLet x,y be the side of each of the squares.

x2 + y2 = 1000

y=(2/3)x-10

substitute (2/3)x-10 for y in the first equation:

x2 + ((2/3)x-10)2 = 1000

Expand and solve for the quadratic equation to get x=30 or x=-270/13.

Reject second solution to get x=30, y=10

See also

http://www.jiskha.com/display.cgi?id=1246414274

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