two tuning forks are struck at the same time. one tuning forkhas a frequency of 20hz while the second tuning fork has a frequency of 226 hz. How many beats will result?
you get the sum and difference, or 206 and 246
i see i don't understand how you got the answer though
To find out how many beats will result when two tuning forks are struck at the same time, we need to understand the concept of beats in sound waves.
When two sound waves of slightly different frequencies interfere with each other, a phenomenon called beats occurs. Beats are periodic variations in amplitude that result from constructive and destructive interference between the waves. The number of beats per second is equal to the difference in frequencies of the two waves.
In this case, we have two tuning forks: one with a frequency of 20 Hz and the other with a frequency of 226 Hz. To find the number of beats, we subtract the frequency of the lower tuning fork from the frequency of the higher tuning fork:
Number of beats = Frequency of higher tuning fork - Frequency of lower tuning fork
= 226 Hz - 20 Hz
= 206 Hz
Therefore, 206 beats will result when the two tuning forks are struck at the same time.