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September 16, 2014

September 16, 2014

Posted by **Breanna** on Tuesday, June 30, 2009 at 12:10am.

2. One leg of a right triangle is 2 1/2 times the other and the area is 20. What are the dimensions?

- Algebra -
**Marth**, Tuesday, June 30, 2009 at 9:32am1.

let x = the length

let (3/4) x = the width

The area of a rectangle = width * height.

area = width*height

12 = x*(3/4)x

12 = (3/4)x^2

12/(3/4) = x^2

16 = x^2

x=4. The answer x=-4 does not make sense in the context of the problem.

2.

let x = leg one

let 2.5x = leg two

The area of a triangle = base*height/2

area = base*height/2

20 = 2.5x*x/2

20 = 2.5x^2/2

20/2.5 = x^2/2

8 = x^2/2

16 = x^2

x=4. Again, the answer x=-4 does not make sense in the context of the problem.

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