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Algebra

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1. The area of a rectangle is 12 and the width is 3/4 the length. What are the dimensions?

2. One leg of a right triangle is 2 1/2 times the other and the area is 20. What are the dimensions?

  • Algebra -

    1.
    let x = the length
    let (3/4) x = the width

    The area of a rectangle = width * height.

    area = width*height

    12 = x*(3/4)x
    12 = (3/4)x^2
    12/(3/4) = x^2
    16 = x^2
    x=4. The answer x=-4 does not make sense in the context of the problem.

    2.
    let x = leg one
    let 2.5x = leg two

    The area of a triangle = base*height/2

    area = base*height/2

    20 = 2.5x*x/2
    20 = 2.5x^2/2
    20/2.5 = x^2/2
    8 = x^2/2
    16 = x^2
    x=4. Again, the answer x=-4 does not make sense in the context of the problem.

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