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December 20, 2014

December 20, 2014

Posted by **jason** on Monday, June 29, 2009 at 11:38pm.

How many pounds of cornmeal should be in the mixture? 200

how many lbs of soybean meal should be in the mixture? 160

can someone tell me if I have this right?

- math -
**Marth**, Tuesday, June 30, 2009 at 10:08amlet x = pounds of soybean meal

let y = pounds of cornmeal

There should be a total of 360 pounds. Therefore, x+y = 360

The protein % is .14. Out of 360 pounds, that would be 360*.14 = 50.4

Therefore, .18x + .09y = 50.4

substitution:

x=360-y

.18(360-y) + .09y = 50.4

64.8 - .18y + .09y = 50.4

-.09y = -14.4

y = 160

x+y = 360

x+160 = 360

x = 200

200 pounds of soybean meal

160 pounds of cornmeal

Checking my work:

.18x + .09y = 50.4

.18*200 + .09*160 = 50.4

50.4 = 50.4

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