Posted by **Sarah** on Monday, June 29, 2009 at 8:14pm.

A potter’s wheel with rotational inertia of 45 kg m2, is spinning freely at 40 rpm. The potter drops a lump of clay onto the wheel where it sticks a distance 1.2 m from the rotational axis at the wheel’s center. If the subsequent angular speed of the wheel is 32 rpm, what is the clay’s mass? (Hint: treat the clay as a point object, so I=mr2)

- Physics -
**bobpursley**, Monday, June 29, 2009 at 8:38pm
Well, final angular momentum is equal to intial.

wf*If=wi*Ii

where If= Ii+ mr^2 so solve for m

change w to rad/sec

- Physics -
**Damon**, Monday, June 29, 2009 at 8:41pm
conserve angular momentum

45 * 40 = (45 + m * 1.2^2) * 32

(no need here to convert rpm to radians per second)

## Answer this Question

## Related Questions

- physics - A potter's wheel is rotating around a vertical axis through its center...
- physics - A potter's wheel having a radius 0.45 m and a moment of inertia of 14....
- Physics - A potter’s wheel of radius 53.13 cm and mass 106.4 kg is freely ...
- physcs - A potter's wheel having a radius 0.55 m and a moment of inertia 11.6 kg...
- Physics - A piece of clay is stuck to the edge of a potter's wheel. Draw a ...
- language - Write the verb in each sentence. Write whether the action is past, ...
- Physics - How does torque equal to <frictional force times radius [of solid ...
- Physics - You are holding the axle of a bicycle wheel with radius 35 cm and mass...
- physics - A large wooden wheel of radius R and the moment of inertia I is ...
- mechanics - Find the total kinetic energy of a 1500 g wheel, 700 mm in diameter...