Posted by **Sarah** on Monday, June 29, 2009 at 8:14pm.

A potter’s wheel with rotational inertia of 45 kg m2, is spinning freely at 40 rpm. The potter drops a lump of clay onto the wheel where it sticks a distance 1.2 m from the rotational axis at the wheel’s center. If the subsequent angular speed of the wheel is 32 rpm, what is the clay’s mass? (Hint: treat the clay as a point object, so I=mr2)

- Physics -
**bobpursley**, Monday, June 29, 2009 at 8:38pm
Well, final angular momentum is equal to intial.

wf*If=wi*Ii

where If= Ii+ mr^2 so solve for m

change w to rad/sec

- Physics -
**Damon**, Monday, June 29, 2009 at 8:41pm
conserve angular momentum

45 * 40 = (45 + m * 1.2^2) * 32

(no need here to convert rpm to radians per second)

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