Monday

March 30, 2015

March 30, 2015

Posted by **sumayya** on Monday, June 29, 2009 at 2:26pm.

- maths -
**bobpursley**, Monday, June 29, 2009 at 2:53pmmultiply the left side by sinAcosA/(sinAcosA)

sin^2A*(cosA+sinA)+cos^2A*(sin+cosA)/ ( )

(cosA+sinA)(sin^2+ cos^2)/ ( )

1/sinA + 1/Cos A

cscA + secA

qed

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