Posted by Mary on Saturday, June 27, 2009 at 10:56am.
I am assuming there is only the one equation
x^2 - 3x - 12 = 0, because what follows makes no sense
First of all your quadratic does not factor, so you will have to either use the quadratic equation formula or complete the square.
let's use the formula:
x = (3 √(9-4(1)(-12))/2
= (3 √57)/2
Use your calculator if you need a decimal equivalent.
Ok i may be dense but i dont ge tthe formula cause when i work out
3 } (9-4(1)(-12))/2
I get 60 not 57, and i dont understand how you got 9 or 4 either
for any quadratic equation
ax^2 + bx + c = 0
x = (-b √(b^2 - 4ac))/(2a)
so in our case
a = 1, b = -3, and c = -12
look at the second example on this page
http://www.nipissingu.ca/calculus/tutorials/quadratics.html
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