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October 20, 2014

October 20, 2014

Posted by **Lissa** on Friday, June 26, 2009 at 12:27pm.

If the function ƒ is defined by ƒ(x) = 2x + 3, and if ƒ(a) = 11, what is the value of a?

A. 4

B. 7

C. 11

D. 17

E. 25

This is the correct answer and the explanation

Here's Why:

If the function ƒ is defined by ƒ(x) = 2x + 3, and ƒ(a) = 11, then ƒ(a) = 2a + 3 = 11. Therefore, a = 11-3/2=4.

I don't understand the rules for functions. Why do you divide 11-3 by 2? Is there a specific formula you follow for them? Thanks for your help!

- Algebra -
**Reiny**, Friday, June 26, 2009 at 12:57pmWhat they were doing is following the rules for 'solving equations'.

the notation

f(x) = 2x + 3 can be written also as

y = 2x + 3, it says the same thing

so when they say f(a) it means that whenever you saw an x has now been replaced by a,

so the 2x + 3 becomes 2a + 3

but you were told that this equals 11

so all you are doing is solving

2a + 3 = 11

Now recall your elementary rules of equations, "whatever you do to one side you must do to the other side"

so lets add -3 to both sides

2a + 3 - 3 = 11 - 3 (I wanted to get rid of +3)

2a = 8 ( I now want to get rid of the 2 in front of a)

divide both sides by 2

2a/2 = 8/2

a = 4

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