Posted by **Jacinta** on Friday, June 26, 2009 at 10:27am.

Find the equation of the line parallel to the line 3x + y = 5 and containing the point (4, – 2).

This is what I got. Is this correct?

y = –3x + 10

- Algebra -
**Anonymous**, Friday, June 26, 2009 at 10:39am
Yes!

- Algebra -
**Jacinta**, Friday, June 26, 2009 at 10:53am
Is my evvaluation correct?

y=mx+b

3x + y = 5

y = -3x+5

y = -2

m = -3

x = 4

b = unknown

Solve For b:

y = -3x + b

-2 = -3(4) + b

-2 = -12 + b

-12 + 10 = -2

10=b

To Check:

y = -3x + b

-2 = -3(4) + b

-2 = -12 + b

-12+10 = b

10 = b

-2 = -3(4) + b

-2 = -12 + 10

-12+10 = -2

b = 10

- Algebra -
**Reiny**, Friday, June 26, 2009 at 12:08pm
A real easy way to do this question is to realize that since they have the same slope, the equations must differ only in the constant.

So let the new equation be

3x + y = c

plug in the point (4,-2)

12 - 2 = c = 10

so your equation is 3x + y = 10

[ BTW, had it asked for a perpendicular line then my opening new equation would have been

x + 3y = c

(notice the slopes would be opposite reciprocals) ]

- Algebra -
**Jacinta**, Friday, June 26, 2009 at 1:08pm
So my work is correct? Thanks for the help!

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