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January 31, 2015

January 31, 2015

Posted by **Jacinta** on Friday, June 26, 2009 at 10:27am.

This is what I got. Is this correct?

y = –3x + 10

- Algebra -
**Anonymous**, Friday, June 26, 2009 at 10:39amYes!

- Algebra -
**Jacinta**, Friday, June 26, 2009 at 10:53amIs my evvaluation correct?

y=mx+b

3x + y = 5

y = -3x+5

y = -2

m = -3

x = 4

b = unknown

Solve For b:

y = -3x + b

-2 = -3(4) + b

-2 = -12 + b

-12 + 10 = -2

10=b

To Check:

y = -3x + b

-2 = -3(4) + b

-2 = -12 + b

-12+10 = b

10 = b

-2 = -3(4) + b

-2 = -12 + 10

-12+10 = -2

b = 10

- Algebra -
**Reiny**, Friday, June 26, 2009 at 12:08pmA real easy way to do this question is to realize that since they have the same slope, the equations must differ only in the constant.

So let the new equation be

3x + y = c

plug in the point (4,-2)

12 - 2 = c = 10

so your equation is 3x + y = 10

[ BTW, had it asked for a perpendicular line then my opening new equation would have been

x + 3y = c

(notice the slopes would be opposite reciprocals) ]

- Algebra -
**Jacinta**, Friday, June 26, 2009 at 1:08pmSo my work is correct? Thanks for the help!

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