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Algebra

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Please Simplify:

(root5 a^7/2)^4 a^3/a^8

So confused, I tried figuring this out but need some help tracing the steps. I would appreciate some feedback! Thanks!

  • Algebra - ,

    I have assumed that the fraction 7/2 is enclosed in parentheses, as follows:

    (sqrt(5)*a(7/2))4 a3/a8

    Since the bases of the exponents are "a" or 5, you only have to apply the following rules of exponents to get your answer of 25a9.

    1. sqrt(5) = 51/2
    2. distributive law:
    (ab)x = ax bx
    3. addition of exponents of same base
    ax ay = ax+y
    4. multiplication of exponents
    (ax )y = axy

    So:
    (sqrt(5)*a(7/2))4 a3/a8
    =(sqrt(5)4*(a(7/2))4) a3-8
    =25 a14 a-5
    =25 a9

  • Algebra - ,

    WOW Thanks for the reply, but I still do not get how we get 25a^9. Can you please further explain. Thanks!

  • Algebra - ,

    I get 25a^9/16? How can this be? Please help, still confused, thanks!

  • Algebra - ,

    If you show your steps, it may help me spot where it has gone wrong.

  • Algebra - ,

    ...
    =(sqrt(5)4*(a(7/2))4) a3-8
    =5(1/2)*4*a(7/2)*4*a3-8
    =25 a14 a-5
    =25 a9

    the denominator 2 in the fraction (7/2) is an exponent and not a simple number. This is probably from where you got the 16.

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