Posted by **Stacy** on Wednesday, June 24, 2009 at 11:24pm.

Let f(x) = 6/x-1 and g(x) = 1+3/x. Please fing the composite function.

This is what i got so far.

=f (1+3/x)

=6/x-1

= =f (1+3/x)

= 6/ [1+3/x - 1]

How do I get the composite?

- Algebra -
**MathMate**, Thursday, June 25, 2009 at 12:07am
The definition of a composite function:

f º g (x) means f (g(x) ), which tells you to work out g(x) first, and then fill that answer into f. See

(Broken Link Removed)

In this case,

f(x) = 6/x-1 and g(x) = 1+3/x

so

f º g (x)

=f(g(x))

=f(**1+3/x**)

=6/(**1+3/x**)-1

=6x/(x+3)-1

=(6x-(x+3))/(x+3)

=(5x-3)/(x+3)

- Algebra -
**Stacy**, Thursday, June 25, 2009 at 12:18am
and the composite function would be?

A.(fog)(x)= (2x)

B.(fog)(x) =2/x

C.(fog)(x)=(6/x-1)(1+3/x

D.(fog)(x)=1+18/x(x-1)

- Algebra -
**MathMate**, Thursday, June 25, 2009 at 12:31am
There is probably a mis-interpretation of the parentheses:

f(x) = 6/**(x-1)** and g(x) = 1+3/x

so

f º g (x)

=f(g(x))

=f(*+3/x*)

=6/(*1+3/x*-1)

=6/(3/x)

=2x

If this is the case, the answer is (A).

- Algebra -
**Stacy**, Thursday, June 25, 2009 at 12:49am
This is what I thought as well. Thanks!

## Answer This Question

## Related Questions

- Algebra - Help please! I got so far with this and stopped because of confusion. ...
- algebra functions - can someone please check my answer For each problem, ...
- calculus - Suppose that f(x)= square root of x and g(x)= 3x-4 and you are asked ...
- functions - For each problem, construct two composite functions, . Evaluate each...
- college algebra - Let f(x) = square root (x + 2) and g(x) = x^2 − 2. ...
- Math - Domain of Composite function - Find the domain of the composite function ...
- algebra functions check my answer - For each problem, construct two composite ...
- Math - Domain of Composite - Find the domain of the composite function . Please ...
- Domain of composite function - Can you please help me with the following ...
- Algebra - Very confused, and in need of help! I got 10 problems like this......

More Related Questions