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October 1, 2014

October 1, 2014

Posted by **Stacy** on Wednesday, June 24, 2009 at 11:24pm.

This is what i got so far.

=f (1+3/x)

=6/x-1

= =f (1+3/x)

= 6/ [1+3/x - 1]

How do I get the composite?

- Algebra -
**MathMate**, Thursday, June 25, 2009 at 12:07amThe definition of a composite function:

f º g (x) means f (g(x) ), which tells you to work out g(x) first, and then fill that answer into f. See

(Broken Link Removed)

In this case,

f(x) = 6/x-1 and g(x) = 1+3/x

so

f º g (x)

=f(g(x))

=f(**1+3/x**)

=6/(**1+3/x**)-1

=6x/(x+3)-1

=(6x-(x+3))/(x+3)

=(5x-3)/(x+3)

- Algebra -
**Stacy**, Thursday, June 25, 2009 at 12:18amand the composite function would be?

A.(fog)(x)= (2x)

B.(fog)(x) =2/x

C.(fog)(x)=(6/x-1)(1+3/x

D.(fog)(x)=1+18/x(x-1)

- Algebra -
**MathMate**, Thursday, June 25, 2009 at 12:31amThere is probably a mis-interpretation of the parentheses:

f(x) = 6/**(x-1)**and g(x) = 1+3/x

so

f º g (x)

=f(g(x))

=f(*+3/x*)

=6/()*1+3/x*-1

=6/(3/x)

=2x

If this is the case, the answer is (A).

- Algebra -
**Stacy**, Thursday, June 25, 2009 at 12:49amThis is what I thought as well. Thanks!

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