Posted by Stacy on Wednesday, June 24, 2009 at 11:24pm.
Let f(x) = 6/x1 and g(x) = 1+3/x. Please fing the composite function.
This is what i got so far.
=f (1+3/x)
=6/x1
= =f (1+3/x)
= 6/ [1+3/x  1]
How do I get the composite?

Algebra  MathMate, Thursday, June 25, 2009 at 12:07am
The definition of a composite function:
f º g (x) means f (g(x) ), which tells you to work out g(x) first, and then fill that answer into f. See
(Broken Link Removed)
In this case,
f(x) = 6/x1 and g(x) = 1+3/x
so
f º g (x)
=f(g(x))
=f(1+3/x)
=6/(1+3/x)1
=6x/(x+3)1
=(6x(x+3))/(x+3)
=(5x3)/(x+3)

Algebra  Stacy, Thursday, June 25, 2009 at 12:18am
and the composite function would be?
A.(fog)(x)= (2x)
B.(fog)(x) =2/x
C.(fog)(x)=(6/x1)(1+3/x
D.(fog)(x)=1+18/x(x1)

Algebra  MathMate, Thursday, June 25, 2009 at 12:31am
There is probably a misinterpretation of the parentheses:
f(x) = 6/(x1) and g(x) = 1+3/x
so
f º g (x)
=f(g(x))
=f(+3/x)
=6/(1+3/x1)
=6/(3/x)
=2x
If this is the case, the answer is (A).

Algebra  Stacy, Thursday, June 25, 2009 at 12:49am
This is what I thought as well. Thanks!
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