Sunday

September 14, 2014

September 14, 2014

Posted by **Veronica** on Tuesday, June 23, 2009 at 6:06pm.

- math -
**Anonymous**, Tuesday, June 23, 2009 at 6:21pmBetween those two points, there's a change in x (the horizontal leg of a right triangle) and a change in y (the vertical leg of a right triangle). The distance between them is therefore the hypotenuse of the right triangle.

x^2+y^2 = distance^2

(it's the Pythagorean Theorem, because the distance IS the hypotenuse)

x is the CHANGE in x, and y is the CHANGE in y (which create the horizontal and vertical legs, respectively).

So:

(-7.5-9.8)^2 + (-5.5--9.9)^2 = (-17.3)^2 + (-5.5+9.9)^2 = (-17.3)^2 + (4.4)^2 = 299.29 + 19.36 = 318.65

ANSWER: The distance between the two points is 318.65 units.

- math -
**Veronica**, Tuesday, June 23, 2009 at 10:07pmthat is the answer i have but it is not correct. i guess i am suppose to reduce it and square the answer. I have tried another problem. Find the distance between the pair of points (-6.2,4.6)(-4.5,0.6) i have the distance as 141.50 and their answer is 4.35. how did they get this answer i squared 141.50 and still did not get 4.35.

- math -
**Anonymous**, Tuesday, June 23, 2009 at 10:50pmWhoops! Forgot to take the square root. Duh!

**Answer this Question**

**Related Questions**

math - Find the distance between the two points. Round an approximate result to ...

Math Question - Jane has two tennis serves, a hard serve and a soft serve. Her ...

jasmine20 - I just wanted to say I have seen you getting better in math as time ...

Math214 - Jane has two tennis serves, a hard serve and a soft serve.Her hard ...

Physics - An athlete starts at point A and runs at a constant speed of 5.40 m/s ...

Math - The old 30-question AHSME was graded as follows: Students were awarded 5 ...

Math (surveying) - I am having a really hard time figuring this problem out. I ...

alg. - Find the slope of the line passing through the points (–2, 1) and (3, 9...

Stats formula - i have a hard time figuring out which formula's to use when ...

Finding a Formula, help please ! - Does anyone know the formula to find any ...