Wednesday
May 27, 2015

Homework Help: Physics

Posted by Physics on Tuesday, June 23, 2009 at 4:20pm.

I'm trying to rearange this
0 = Xo + 2^-1 a t^2
for t
I've been told that it is

(a^-1 2x)^(2^-1)

but I do not see how please show me step by step how you get that

0 - Xo = Xo - Xo + 2^-1 a t^2
(-Xo = 2^-1 a t^2) a^-1 2
(a^-1 (2-Xo) = t^2)^(2^-1)
(a^-1 (2 - Xo))^(2^-1)

please show me how to do this as i'm getting negetive number imaginary
show me step by step how to rearang please not just the rearanged equation but how you rearange it because i do not get it

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

Members