Posted by **Physics** on Tuesday, June 23, 2009 at 4:20pm.

I'm trying to rearange this

0 = Xo + 2^-1 a t^2

for t

I've been told that it is

(a^-1 2x)^(2^-1)

but I do not see how please show me step by step how you get that

0 - Xo = Xo - Xo + 2^-1 a t^2

(-Xo = 2^-1 a t^2) a^-1 2

(a^-1 (2-Xo) = t^2)^(2^-1)

(a^-1 (2 - Xo))^(2^-1)

please show me how to do this as i'm getting negetive number imaginary

show me step by step how to rearang please not just the rearanged equation but how you rearange it because i do not get it

## Answer this Question

## Related Questions

- Physics PLEASE - I'm trying to solve this problem Calculate (a) how long it took...
- precalc - How would you find the inverse of these two functions: f(x)=4/(x-4)^2 ...
- Physics - Can someone please show me step by step how to normalize e^-5x in the ...
- Algebra 1--Step-by-Step - Can someone show me how to solve these step-by-step? ...
- TRIGONOMETRY - Can someone please show me step by step how to calculate the ...
- Trig - Find the value of the six trigonometric functions. t = 7(pi)/4 Can you ...
- math - An equation and the steps to solve it are shown below: 3x − one ...
- math - An equation and the steps to solve it are shown below: 3x − one ...
- Physics PLEASE - I'm trying to derive the formula v^2 = v0^2 + 2a(x-x0) were ...
- Quick math help - In which step below does a mistake first appear in simplifying...

More Related Questions