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September 2, 2014

September 2, 2014

Posted by **Breanna** on Monday, June 22, 2009 at 10:40pm.

a. (1-2i)(1+3i)

b. (3-5i)(8-2i)

- Algebra -
**bobpursley**, Monday, June 22, 2009 at 10:59pmUse FOIL to multiply them out.

- Algebra -
**Breanna**, Monday, June 22, 2009 at 11:15pmIS this correct, i notice that i^2 = -1 what does this mean?

(1-2i)(1+3i)

=1+3i-2i-6i^2

=1+ i-6i^2

= 1+i-6i

- Algebra -
**bobpursley**, Monday, June 22, 2009 at 11:51pmno, 6i^2 is 6*(-1)

so the last term is +6 and the final answer is

7+i

- Algebra -
**Breanna**, Tuesday, June 23, 2009 at 12:11amSo did I do any of this correct? What do I need to fix?

- Algebra -
**MathMate**, Tuesday, June 23, 2009 at 12:56amYou have basically done it correctly, but omitted to change the sign of the last term because i

^{2}=-1

(1-2i)(1+3i)

=1+3i-2i-6i^2

=1+ i-6i^2

= 1+i**+**6i

- Algebra -
**MathMate**, Tuesday, June 23, 2009 at 12:57amOops, it should read:

(1-2i)(1+3i)

=1+3i-2i-6i^2

=1+ i-6i^2

= 1+i**+**6

=**7+i**

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