Posted by matt on .
The heat capacity of object B is twice that of object A. Initially A is at 300 K and B is at 450 K. They are placed in thermal contact and the combination is isolated. The final temperature of both objects is:

chemistry 
GK,
Let the heat capacity of A = c. The heat capacity of B is 2c. Let the final temperature be T.
The heat lost by B when A and Be are placed together is: (2c)(450T)
The heat gained by A is (c)(T300).
Assuming the Law of conservation of Energy holds, and there are no heat losses (heat transferred elsewhere),
(2c)(450T) = (c)(T300)
Solve for T. 
chemistry 
GK,
The basic relationships above are:
1. Heat transferred = (heat capacity)(temperature change), or
deltaH = C•(T2T1)
( T1, T2 = initial and final temperatures )
2. Heat lost by B = Heat gained by A 
chemistry 
value 400k,
400k