Posted by **matt** on Monday, June 22, 2009 at 5:43pm.

The heat capacity of object B is twice that of object A. Initially A is at 300 K and B is at 450 K. They are placed in thermal contact and the combination is isolated. The final temperature of both objects is:

- chemistry -
**GK**, Monday, June 22, 2009 at 7:40pm
Let the heat capacity of A = c. The heat capacity of B is 2c. Let the final temperature be T.

The heat lost by B when A and Be are placed together is: (2c)(450-T)

The heat gained by A is (c)(T-300).

Assuming the Law of conservation of Energy holds, and there are no heat losses (heat transferred elsewhere),

(2c)(450-T) = (c)(T-300)

Solve for T.

- chemistry -
**GK**, Monday, June 22, 2009 at 10:06pm
The basic relationships above are:

1. Heat transferred = (heat capacity)(temperature change), or

deltaH = C•(T2-T1)

( T1, T2 = initial and final temperatures )

2. Heat lost by B = Heat gained by A

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