Posted by Sarah on .
A 61 kg skier on level snow coasts 184 m to stop from a speed of 12.0 m/s (A) use the work energy principle to find the coefficient of kinetic friction between the skis and the snow. B) suppose a 75 kg skier with twice the starting speed coasted the same distance before stopping, find the coefficent of kinetic friction between the skiers skis and the snow

Physics 
bobpursley,
Didn't I go through this with you before? Set initial KE equal to mu*mg*distance.
If you don't understand that, explain. I can't read minds. 
Physics 
Sarah,
sorry about that...
I got your 1/2 m v^2=mu*mg*distance
so I did 1/2(61kg)(12.0 m.s)^2 = mu * (what do i put for mg) and distance is 184 m right? 
Physics 
bobpursley,
m is mass, itis given as 61kg, g is 9.8m/s^2

Physics 
Sarah,
so its the 61(9.8)
so then the final formula would look like
1/2(61kg)(12.0 m.s)^2 = mu * (61kg)(9.8m/s^2)(184m)
solve for mu right? 
Physics 
bobpursley,
correct.

Physics 
Sarah,
i did the left side of the equation = 4392
and the right side i got 109995.2
so i did 4392/109995.2 = .039929