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March 27, 2017

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A 61 kg skier on level snow coasts 184 m to stop from a speed of 12.0 m/s (A) use the work energy principle to find the coefficient of kinetic friction between the skis and the snow. B) suppose a 75 kg skier with twice the starting speed coasted the same distance before stopping, find the coefficent of kinetic friction between the skiers skis and the snow

  • Physics - ,

    Didn't I go through this with you before? Set initial KE equal to mu*mg*distance.

    If you don't understand that, explain. I can't read minds.

  • Physics - ,

    sorry about that...
    I got your 1/2 m v^2=mu*mg*distance

    so I did 1/2(61kg)(12.0 m.s)^2 = mu * (what do i put for mg) and distance is 184 m right?

  • Physics - ,

    m is mass, itis given as 61kg, g is 9.8m/s^2

  • Physics - ,

    so its the 61(9.8)

    so then the final formula would look like
    1/2(61kg)(12.0 m.s)^2 = mu * (61kg)(9.8m/s^2)(184m)

    solve for mu right?

  • Physics - ,

    correct.

  • Physics - ,

    i did the left side of the equation = 4392
    and the right side i got 109995.2

    so i did 4392/109995.2 = .039929

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