Posted by **Sarah** on Monday, June 22, 2009 at 1:36pm.

A 61 kg skier on level snow coasts 184 m to stop from a speed of 12.0 m/s (A) use the work energy principle to find the coefficient of kinetic friction between the skis and the snow. B) suppose a 75 kg skier with twice the starting speed coasted the same distance before stopping, find the coefficent of kinetic friction between the skiers skis and the snow

- Physics -
**bobpursley**, Monday, June 22, 2009 at 1:40pm
Didn't I go thru this with you before? Set initial KE equal to mu*mg*distance.

If you don't understand that, explain. I can't read minds.

- Physics -
**Sarah**, Monday, June 22, 2009 at 1:46pm
sorry about that...

I got your 1/2 m v^2=mu*mg*distance

so I did 1/2(61kg)(12.0 m.s)^2 = mu * (what do i put for mg) and distance is 184 m right?

- Physics -
**bobpursley**, Monday, June 22, 2009 at 1:49pm
m is mass, itis given as 61kg, g is 9.8m/s^2

- Physics -
**Sarah**, Monday, June 22, 2009 at 1:53pm
so its the 61(9.8)

so then the final formula would look like

1/2(61kg)(12.0 m.s)^2 = mu * (61kg)(9.8m/s^2)(184m)

solve for mu right?

- Physics -
**bobpursley**, Monday, June 22, 2009 at 1:55pm
correct.

- Physics -
**Sarah**, Monday, June 22, 2009 at 2:03pm
i did the left side of the equation = 4392

and the right side i got 109995.2

so i did 4392/109995.2 = .039929

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