Posted by Z32 on Monday, June 22, 2009 at 12:59am.
make a sketch showing the ladder touching the fence and making contact with the wall.
let the angle at the base of the ladder be ß
draw a horizontal from the top of the fence to the wall, then the angle the ladder makes with that line is ß, giving up 2 similar right-angled triangles
the ladder has length L1 above the fence and L2 below the fence
cosß = 7/L1 ---> L1 = 7secß
sinß = 5/L2 ---> L2 = 5cscß
so L = 7secß + 5sinß = 7(cosß)^-1 + 5(sinß)^-1
dL/dß = -7(cosß)^-2(-sinß) - 5(sinß)^-2(cosß)
simplifying and setting equal to zero gives me
7sinß/(cosß)^2 = 5cosß/(sinß)^2
cross-multiplying:
7(sinß)^3 = 5(cosß)^3 or
(tanß)^3 = 5/7
tanß = (5/7)^(1/3) = .8939..
ß=41.7936 degrees
sub that back into L1 and L2, add them up , ....
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