Saturday

March 28, 2015

March 28, 2015

Posted by **Z32** on Monday, June 22, 2009 at 12:58am.

- Calculus -
**drwls**, Monday, June 22, 2009 at 6:07amLet x and y be the two side lengths of the full rectangle. The length x will be divided in two. The total lengths of fence needed will be

L = 2x + 3y.

You know that x y = 5,189,400 ft^2

dL/dx = d/dx (2x + 3*5,189,400/x)

= 2 - 15,568,200/x^2 = 0 at minimum L

x^2 = 7,784,100

x = 2790 ft y = 1860

Quantity of fence needed = 2x + 3y = ?

**Answer this Question**

**Related Questions**

Calculus - A rancher wants to fence in an area of 500000 square feet in a ...

Calc - A rancher wants to fence in an area of 1500000 square feet in a ...

CALC - A rancher wants to fence in an area of 1500000 square feet in a ...

math - I've tried this many times, but I keep getting a really big answer. A ...

calculus - A rancher wants to fence in an area of 3000000 square feet in a ...

Calculus-Applied Optimization Quiz Problem - A rancher wants to fence in a ...

area and perimeter - a farmer wishes to build a fence around a rectangular field...

Calculus - A rancher wants to make an animal pen by fencing in an area of ...

math - A rectangular field is to be enclosed by a fence. Two fences parallel to ...

calculus (optimization) - a rectangular study area is to be enclosed by a fence ...