Posted by **Z32** on Monday, June 22, 2009 at 12:58am.

A rancher wants to fence in an area of 5189400 square feet in a rectangular field and then divide it in half with a fence down the middle parallel to one side. What is the shortest length of fence that the rancher can use?

- Calculus -
**drwls**, Monday, June 22, 2009 at 6:07am
Let x and y be the two side lengths of the full rectangle. The length x will be divided in two. The total lengths of fence needed will be

L = 2x + 3y.

You know that x y = 5,189,400 ft^2

dL/dx = d/dx (2x + 3*5,189,400/x)

= 2 - 15,568,200/x^2 = 0 at minimum L

x^2 = 7,784,100

x = 2790 ft y = 1860

Quantity of fence needed = 2x + 3y = ?

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