Homework Help Forum: chemistry

Posted by dan on Sunday, June 21, 2009 at 3:27pm.

ok heres my question, nitrogylcerin decomposes: 4c3h4(no5)3 --->12co2(g) +10h20(g)+6n2(g)+02(g) whats is the max pressure that a 10.0L container will be able to withstand if 5.00 Nitroglycerin decomposes at temp of 1250c mm of nitroglycerin =227 g/m i got 2.00atm b) what are the partial pressures c02=.828 h20=.690 n2=.414 02=.0690 can u show me the method to do the total pressure. The rest i can do myself thanks again

• chemistry - DrBob222, Sunday, June 21, 2009 at 5:41pm

  See the formula for nitroglycerin here. Which formula is correct?http://en.wikipedia.org/wiki/Nitroglycerin

  
  

• chemistry - dan, Sunday, June 21, 2009 at 7:04pm

  the formula is given 4c3h4(no5)3 --->12co2(g) +10h20(g)+6n2(g)+02(g)

  
  

• chemistry - DrBob222, Sunday, June 21, 2009 at 10:09pm

  Your equation isn't balanced. 16 H on the left (and you should try to capitalize those letters that need it) and I see 20 on the right. 60 O on the left and 36 on the right.

  
  

• chemistry - dan, Monday, June 22, 2009 at 3:57am

  it was given so we dont have to. I think the teacher is just trying to show us how to use the mole ratios to get partial pressures

  
  

• chemistry - dan, Monday, June 22, 2009 at 4:05am

  here this might help 4 C3H5(NO3)3(l) → 12 CO2(g) + 10 H2O(g) + 6 N2(g) + O2(g) I must have copied it wrong into the browser. sorry...

  
  

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