Tuesday
October 21, 2014

Homework Help: chemistry

Posted by dan on Sunday, June 21, 2009 at 3:27pm.

ok heres my question,


nitrogylcerin decomposes:

4c3h4(no5)3 --->12co2(g) +10h20(g)+6n2(g)+02(g)

whats is the max pressure that a 10.0L container will be able to withstand if 5.00 Nitroglycerin decomposes at temp of 1250c

mm of nitroglycerin =227 g/m

i got 2.00atm

b) what are the partial pressures

c02=.828
h20=.690
n2=.414
02=.0690


can u show me the method to do the total pressure. The rest i can do myself

thanks again

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