Posted by priya on Sunday, June 21, 2009 at 4:40am.
The positive integers +1, +3 and +5 are not of that form, unless q can also be zero.
The difference between 6q + 5 and 6q' +1, if q' = q+1 , is
[6(q+1) + 1]-[6q +5] = 2
That means that by increasing q by 1 when you get to 6q+5, the next number will be 2 greater, so that all odd numbers can be created. All one has to do is pick the next integer q when you get to 6q +5, and start over at 6q' +1
Related Questions
math - Show that any positive odd integer is of the form 6q+1, 6q+3 or 6q+5, ...
Algebra - Which of the following expressions equals the sum of the binomial ...
Math - (6q^6)^-4 When I worked this I got 1/1296q^24. One of the choices given ...
algebra - i need help on these three..thank you...find the real number solutions...
MATH - Find the only positive integer whose cube is the sum of the cubes of ...
algebra 2 - i really need help on these..i dont understand ....i need to find ...
math - show that any positive integer is of the form 4q, 4q+2, where q is any ...
math - Show that any positive integer is of the form 4q, 4q+2, where q is any ...
Math - When you add a positive integer and a negative integer, you sometimes get...
maths - prove that any odd positive integer of 8q+1,where q is any integer?
For Further Reading
