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September 20, 2014

September 20, 2014

Posted by **Aoi** on Friday, June 19, 2009 at 8:58am.

1. Show that the function f(x)= x^3 - 3x^2 + 9x - 5 is increasing with x for all real values of x.

f'(x)=3x^2-6x+9

=3(x^2-2x+3)

=3[x^2 - 2x + (-2/2)^2 + 3 - (-2/2)^2]

= 3[ (x-1)^2 + 2]

=3(x-1)^2 + 6

?!! The correct answer is supposed to be f'(x)=3(x-1)^2 is ≥0 for all real values of x. Did i do the completing square wrongly?? This same thing happened with the second question

2. Show that f(x) = -2x^2 + 3x^2 - 2x + 4 decreases for all real values of x.

The correct answer for this one is f'(x) = -6(x-1/2)^2 - 1/2 <0 for all real values of x

- Maths integration -
**bobpursley**, Friday, June 19, 2009 at 9:11am1. You did it correctly.

if the first term (x-1)^2 is positive for all x, then that term +6 is positive for all x.

2. Your f' does not match the degree of f(x). I don't know what you meant.

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