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October 31, 2014

October 31, 2014

Posted by **Aoi** on Friday, June 19, 2009 at 8:45am.

Find the value of k for which a-3b is a factor of a^4-7a^2b^2 + kb^4

Hence, for this value of k, factorise a^4 - 7a^2b^2 + kb^4 completely.

I tried to do long division for the question, but couldnt. Is there any other methods?

- Polynomials help -
**bobpursley**, Friday, June 19, 2009 at 9:02amLong division works quite nicely

http://calc101.com/webMathematica/long-divide.jsp#topdoit

Now if a=0, you are dividing

kb^4 by -3b

and if a=1 and b=2 you are dividing

1-7*4+16k by -5 or (-27+16k)/-5 and if that is to come out as an integer, then

-27+16k is a multiple of 5 which means than in 16k has to be ???8 which means k is now a multiple of 3 and ends in 8. Hmmmm. -18 works.

Do the long division.

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