Friday

January 30, 2015

January 30, 2015

Posted by **Arisa** on Friday, June 19, 2009 at 8:40am.

Evaluate the integrals:

limit 0 to pi/4 ∫ [sec^2x]/[5+tanx] dx

limit 0 to pi/6 ∫ [3cos3x]/[3+sin3x] dx

limit 0 to 3 ∫ [2x-1]/[x^2-x+1] dx

__________________________________________________________

By squaring sin^2 + cos^2, show that sin^4x + cos^4x = 1/4 (3+cos4x)

Hence, evaluate ∫(sin^4x+cos^4x) dx

(limit from 0 to pi/8)

__________________________________________________________

How do i express (2x+1)/(x+3) in the form of p + q/(x+3)???

**Answer this Question**

**Related Questions**

Help Evaluating Integrals - 1.) ∫ (2)/(x-4) dx 2.) ∫ sec^2x tanx dx ...

Integration? - Use the derivatives of sinx and cosx to show that d/dx [tanx] = ...

calculus - Integration - evaluate ∫sec^7 x tanx dx

Calculus - I'm having trouble reversing the order of integration of ∫&#...

calculus (check my work please) - Not sure if it is right, I have check with the...

Calculus AP - I'm doing trigonometric integrals i wanted to know im doing step ...

maths... - Differentiate ln [x+√(x^2+1)] with respect to x hence evaluate ...

Calculus - evaluating integrals - I'm really having trouble with this current ...

maths... - This is the entire question: A curve has the equation y=(x+2)√(...

calculus - The following definite integral can be evaluated by subtracting F(B...