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September 5, 2015

Homework Help: Please check my maths?

Posted by holly on Friday, June 19, 2009 at 6:34am.

How should i do this question??

it says:

find the equation of the tangent to the curve y=(x-2)^3 at the point (3,1). calculate the coordinates of the point where this tangent meets the curve again.

I know how to get the first part, if i'm not wrong, it's y = 3x - 8

but no matter how i do, i cant get another point that is meeting the curve again!

This is what i did for the second part:

y=3x-8 ---- (1)
y=(x-2)^3 ----(2)

(x-2)^3 - 3x + 8 = 0
simplify:
x^3 - 6x^2 + 9x = 0
x^2 - 6x + 9 = 0
factorize:
(x-3)^2=0
!?!??!

I'm pretty sure i did something wrong...

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