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February 1, 2015

February 1, 2015

Posted by **Bailey** on Friday, June 19, 2009 at 5:58am.

differentiate (2ax^2 + bx)/(bx^3 - cx)

- Maths Differentiation -
**Writeacher**, Friday, June 19, 2009 at 7:45amBailey, Andrea, Danny, Riley, anabelle, holly, LILLY, zachary, I'm stumped -- or whoever!

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- Maths Differentiation -
**drwls**, Friday, June 19, 2009 at 8:25amTreat the function as the ratio

f(x) = u(x)/v(x)

and use the formula for the derivative of the ratio of two functions

df/dx = [v du/dx - u dv/dx ]/ v^2

The rest is easy.

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