Posted by **Gweedo8** on Thursday, June 18, 2009 at 2:15pm.

(L2bar/mol2) (L/mol)

Acetylene 4.448 0.05136

Calculate the difference in pressure (in atm) when 100.0g of acetylene acts as an ideal gas versus as a real gas in a 100L tank at a temperature of 1000K.

- chemistry -
**Gweedo8**, Thursday, June 18, 2009 at 2:47pm
(L2bar/mol2) (L/mol)

Acetylene 4.448 0.05136

Calculate the difference in pressure (in atm) when 100.0g of acetylene acts as an ideal gas versus as a real gas in a 100L tank at a temperature of 1000K.

- chemistry -
**GK**, Thursday, June 18, 2009 at 6:42pm
1) Change 100.0g C2H2 to moles (n)

2) Calculate the **ideal** pressure using the Ideal Gas Law:

PV = nRT, P = nRT/V

3) Calculate the **real** pressure using the Van der Waals Equation. You can find the equation here:

http://hyperphysics.phy-astr.gsu.edu/Hbase/Kinetic/waal.html

Constants "a" and "b" for acetylene can be found here:

http://en.wikipedia.org/wiki/Van_der_Waals_constants_(data_page)

The difference between P(ideal) and P(real) can be found by subtracting the smaller from the larger one.

[Be prepared to spend some time on this problem]

- chemistry -
**Juggernaut**, Friday, June 19, 2009 at 11:14am
HERE IS MY HOMEWORK:

I have been trying the real gases homework for hours and am completely stuck. This is what I have been attempting to make work. First I found the moles then plugged in all the other variables.

100gC2H2/26.0373g/mol=3.84mol C2H2=n

P=nRT/(V-nb)-an^2/V^2

P= n R T /(V - n b) - a n^2 / V^2

319.49=3.84x8.3145x1000/(100-3.84x.05136)-4.39x3.84^2/100^2

319.49 is not the correct answer and I have only confused myself further and further trying to understand this. At this point I am just pushing buttons on my calculator hoping for a miracle. Please release me from my torture:)

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