Posted by **Breanna** on Wednesday, June 17, 2009 at 2:14pm.

Suppose a farmer has 120 feet of fencing to make a rectangular barnyard enclosure. If the enclosure is x feet long, express the area A of the enclosure as a function of the length x. Briefly explain.

- Math -
**bobpursley**, Wednesday, June 17, 2009 at 2:50pm
if length is x, then width is (120-2x)/2

Area is then length x width or

x * (60-x)

- Math -
**Breanna**, Wednesday, June 17, 2009 at 2:55pm
A(x) = 60x – x2

A(x) = 120x – x2

A(x) = x2 – 30x

Are any of these the answers?

- Math -
**Breanna**, Wednesday, June 17, 2009 at 2:56pm
The 2 meaning squared of course so

A(x) = 60x – x^2

A(x) = 120x – x^2

A(x) = x^2 – 30x

- Math -
**bobpursley**, Wednesday, June 17, 2009 at 3:39pm
x(60-x)=60x-x^2

- Math -
**Breanna**, Wednesday, June 17, 2009 at 3:45pm
So A is the answer then?

A(x) = 60x – x^2

This was my first guess, was I correct?

- Math -
**Robert**, Wednesday, June 17, 2009 at 3:47pm
what is the square root of negtive 80

- Math -
**Breanna**, Wednesday, June 17, 2009 at 3:56pm
I do not know. Does this have anything to do with my problem?

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