Posted by **Physics** on Wednesday, June 17, 2009 at 2:29am.

I'm given a spring that has a mass of 100 g and a constant of 22 N/m with an A of 5 cm

I belive the A is amplitude

and I'm asked for the Total Energy which i don't know how to do

the max velocity also have no idea how to do

and the max force which i don't know how to do

Damon told me this

m = 100 grams = .1 kg

k = 22 N/m

A = 5 cm = .05 m

y = .05 sin w t

w = sqrt (k/m)

you could solve for w

then maximum stretch = .05 m and velocity is zero there so

Maximum potential energy = maximum energy = (1/2) k .05^2 (This is because the kinetic energy and velocity are zero when the spring is stretched maximum)

Max force = k A

to get maximum velocity

(1/2) m v^2 = max kinetic energy = max total energy = max potential energy which we know

Does this mean that maximum energy is

(1/2)ka^2

just making sure here

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