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Posted by Amy on Tuesday, June 16, 2009 at 8:10pm.

Show that f is continuous on (-infinity, infinity). f(x) = x^2 if x<1 and the square root of x if x is greater than or equal to 1. I'm not entirely sure how to start this. Help is greatly appreciated :)

f(1) = 1 For x<1, the function approaches 1 as x->1 from below. Therefore the function is continuous at x=1. It is also defined and continuous for x>1 and x<1. Therefore it is continuous on (-infinity, infinity)

Many thanks!

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