Posted by **Laurie** on Tuesday, June 16, 2009 at 7:56pm.

Consider the line with equation

5x – 2y = 10.

(a) Find the y-intercept for the given line.

(b) Find the slope for a line parallel to the given line.

(c) Find the slope for a line perpendicular to the given line.

- Algebra -
**Laurie**, Tuesday, June 16, 2009 at 8:05pm
(a) Find the y-intercept for the given line.

(b)Find the slope for a line parallel to the given line.

(c) Find the slope for a line perpendicular to the given line.

- Algebra -
**Damon**, Tuesday, June 16, 2009 at 8:09pm
y intercept is when x = 0

-2y = 10

y = -5

2 y = 5 x - 10

y = (5/2) x = 5

so m, the slope, = (5/2)

m'= -1/m

m' = -2/5

- Algebra -
**Laurie**, Tuesday, June 16, 2009 at 8:20pm
This is interesting, I got the first one correct for y = -5 because x = 0 but still do not get how you come up with 5/2 for the slope of the parallel line and the slope of the perpendicular one either? Can you please explain. Thanks!

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