Posted by AP Physics on Tuesday, June 16, 2009 at 7:28pm.
As for the stair problem, you have the right idea. The work, mgh, goes into increasing the potential energy.
accelerates starting from rest
d = (1/2) a t^2
5 meters = (1/2) a (1.75)^2
solve for a, the acceleration
m = 100 grams = .1 kg
k = 22 N/m
A = 5 cm = .05 m
y = .05 sin w t
w = sqrt (k/m)
you could solve for w
then maximum stretch = .05 m and velocity is zero there so
Maximum potential energy = maximum energy = (1/2) k .05^2 (This is because the kinetic energy and velocity are zero when the spring is stretched maximum)
Max force = k A
to get maximum velocity
(1/2) m v^2 = max kinetic energy = max total energy = max potential energy which we know
Thank You
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